p^2+14p+11=-2

Solution for p^2+14p+11=-2 equation:

p^2+14p+11=-2

We move all terms to the left:

p^2+14p+11-(-2)=0

We add all the numbers together, and all the variables

p^2+14p+13=0

a = 1; b = 14; c = +13;
Δ = b2-4ac
Δ = 142-4·1·13
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-12}{2*1}=\frac{-26}{2}
=-13
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+12}{2*1}=\frac{-2}{2}
=-1
$